# Molar Mass Of Gold

Start studying Chemistry - Moles. Learn vocabulary, terms, and more with flashcards, games, and other study tools. The molar mass of gold is 196.97 g/mol. To find this number, multiply the atomic mass by the molar mass constant, which is one gram per one mole because gold in its elemental form is a single atom. Molar mass is a physical property of substances that describes the mass of a substance divided by the amount of the substance present.

- Molar Mass Calculator
- List Of Molar Masses
- Molar Mass Of Gold(iii) Chloride
- Convert Molar Mass To Grams

Learning Objectives

- Determine the molar mass for a compound or molecule.
- Convert from moles to grams and grams to moles.

In the previous section we defined molar mass as the mass of one mole of anything, or the mass of 6.022 x 10^{23} of that thing. In this section we're going to look at how this applied to molecules or compounds.

## Molar Mass

**Molar mass** is defined as the mass of one mole of representative particles of a substance. By looking at a periodic table, we can conclude that the molar mass of lithium is (6.94 : text{g}), the molar mass of zinc is (65.38 : text{g}), and the molar mass of gold is (196.97 : text{g}). Each of these quantities contains (6.02 times 10^{23}) atoms of that particular element. The units for molar mass are grams per mole or (text{g/mol}).

### Molar Masses of Compounds

The molecular formula of the compound carbon dioxide is (ce{CO_2}). One molecule of carbon dioxide consists of 1 atom of carbon and 2 atoms of oxygen. We can calculate the mass of one molecule of carbon dioxide by adding together the masses of 1 atom of carbon and 2 atoms of oxygen.

[12.01 : text{amu} + 2 left( 16.00 : text{amu} right) = 44.01 : text{amu}]

The **molecular mass** of a compound is the mass of one molecule of that compound. The molecular mass of carbon dioxide is (44.01 : text{amu}).

The molar mass of any compound is the mass in grams of one mole of that compound. One mole of carbon dioxide molecules has a mass of (44.01 : text{g}), while one mole of sodium sulfide formula units has a mass of (78.04 : text{g}). The molar masses are (44.01 : text{g/mol}) and (78.04 : text{g/mol}) respectively. In both cases, that is the mass of (6.02 times 10^{23}) representative particles. The representative particle of (ce{CO_2}) is the molecule, while for (ce{Na_2S}) it is the formula unit.

Example (PageIndex{1})

Calcium nitrate, (ce{Ca(NO_3)_2}), is used as a component in fertilizer. Determine the molar mass of calcium nitrate.

**Solution:**

*Step 1: List the known and unknown quantities and plan the problem*.

__Known__

- Formula (= ce{Ca(NO_3)_2})
- Molar mass (ce{Ca} = 40.08 : text{g/mol})
- Molar mass (ce{N} = 14.01 : text{g/mol})
- Molar mass (ce{O} = 16.00 : text{g/mol})

__Unknown__

Molar mass (ce{Ca(NO_3)_2})

First we need to analyze the formula. Since the (ce{Ca}) lacks a subscript, there is one (ce{Ca}) atom per formula unit. The 2 outside the parentheses means that there are two nitrate ions per formula unit and each nitrate ion consists of one nitrogen atom and three oxygen atoms per formula unit. Thus, (1 : text{mol}) of calcium nitrate contains (1 : text{mol}) of (ce{Ca}) atoms, (2 : text{mol}) of (ce{N}) atoms, and (6 : text{mol}) of (ce{O}) atoms.

*Step 2: Calculate*

Use the molar masses of each atom together with the number of atoms in the formula and add together.

[1 : text{mol} : ce{Ca} times frac{40.08 : text{g} : ce{Ca}}{1 : text{mol} : ce{Ca}} = 40.08 : text{g} : ce{Ca}]

[2 : text{mol} : ce{N} times frac{14.01 : text{g} : ce{N}}{1 : text{mol} : ce{N}} = 28.02 : text{g} : ce{N}]

[6 : text{mol} : ce{O} times frac{16.00 : text{g} : ce{O}}{1 : text{mol} : ce{O}} = 96.00 : text{g} : ce{O}]

Molar mass of (ce{Ca(NO_3)_2} = 40.08 : text{g} + 28.02 : text{g} + 96.00 : text{g} = 164.10 : text{g/mol})

Here are some further examples:

- The mass of a hydrogen atom is 1.0079 amu; the mass of 1 mol of hydrogen atoms is 1.0079 g.
- Elemental hydrogen exists as a diatomic molecule, H
_{2}. One molecule has a mass of 1.0079 + 1.0079 = 2.0158 amu, while 1 mol H_{2}has a mass of 2.0158 g. - A molecule of H
_{2}O has a mass of about 18.01 amu; 1 mol H_{2}O has a mass of 18.01 g. - A single unit of NaCl has a mass of 58.45 amu; NaCl has a molar mass of 58.45 g.

In each of these moles of substances, there are 6.022 × 10^{23} units:

- 6.022 × 10
^{23}atoms of H - 6.022 × 10
^{23}molecules of H_{2}and H_{2}O, - 6.022 × 10
^{23}units of NaCl ions.

These relationships give us plenty of opportunities to construct conversion factors for simple calculations.

Example (PageIndex{2})

What is the molar mass of C_{6}H_{12}O_{6}?

**Solution**

To determine the molar mass, we simply add the atomic masses of the atoms in the molecular formula but express the total in grams per mole, not atomic mass units. The masses of the atoms can be taken from the periodic table.

6 C = 6 × 12.011 | = 72.066 |

12 H = 12 × 1.0079 | = 12.0948 |

6 O = 6 × 15.999 | = 95.994 |

TOTAL | = 180.155 g/mol |

Per convention, the unit *grams per mole* is written as a fraction.

Exercise (PageIndex{2})

What is the molar mass of AgNO_{3}?

*Answer*

169.87 g/mol

Knowing the molar mass of a substance, we can calculate the number of moles in a certain mass of a substance and vice versa, as these examples illustrate. The molar mass is used as the conversion factor.

Example (PageIndex{3})

What is the mass of 3.56 mol of HgCl_{2}? The molar mass of HgCl_{2} is 271.49 g/mol.

**Solution**

Use the molar mass as a conversion factor between moles and grams. Because we want to cancel the mole unit and introduce the gram unit, we can use the molar mass as given:

[3.56, cancel{mol, HgCl_{2}}times frac{271.49, g, HgCl_{2}}{cancel{mol, HgCl_{2}}}=967, g, HgCl_{2}]

Exercise (PageIndex{3})

What is the mass of 33.7 mol of H_{2}O?

*Answer*

607 g

Example (PageIndex{4})

How many moles of H_{2}O are present in 240.0 g of water (about the mass of a cup of water)?

**Solution**

Use the molar mass of H_{2}O as a conversion factor from mass to moles. The molar mass of water is (1.0079 + 1.0079 + 15.999) = 18.015 g/mol. However, because we want to cancel the gram unit and introduce moles, we need to take the reciprocal of this quantity, or 1 mol/18.015 g:

[240.0, cancel{g, H_{2}O}times frac{1, mol, H_{2}O}{18.015cancel{g, H_{2}O}}=13.32, mol, H_{2}O]

Exercise (PageIndex{4})

How many moles are present in 35.6 g of H_{2}SO_{4} (molar mass = 98.08 g/mol)?

*Answer*

0.363 mol

Other conversion factors can be combined with the definition of mole-density, for example.

Example (PageIndex{5})

The density of ethanol is 0.789 g/mL. How many moles are in 100.0 mL of ethanol? The molar mass of ethanol is 46.08 g/mol.

**Solution**

Here, we use density to convert from volume to mass and then use the molar mass to determine the number of moles.

[100cancel{ml}: ethanoltimes frac{0.789, g}{cancel{ml}}times frac{1, mol}{46.08, cancel{g}}=1.71, mol, ethanol]

Exercise (PageIndex{5})

If the density of benzene, C_{6}H_{6}, is 0.879 g/mL, how many moles are present in 17.9 mL of benzene?

*Answer*

0.201 mol

### Converting between mass, moles or atoms of a compound to mass, moles or atoms of its elements

Now that we know how to convert from atoms to molecules, from molecules to moles and from moles to grams we can string these conversion factors together to solve more complicated problems.

Example (PageIndex{6}): Converting between grams and Atoms

How many atoms of hydrogen are in 4.6 g of CH_{3}OH?

**Solution**

First we need to determine the mass of one mole of methane (CH_{3}OH).

Using the periodic table to find the mass for each mole of our elements we have:

[1, mole, C ,= 1, cancel{mole, C},times left(frac{12.011, g, C}{1,cancel{mole,C}} right), = 12.011 , g, C]

[4, mole, H ,= 4, cancel{mole, H},times left(frac{1.008, g, H}{1,cancel{mole,H}} right), = 4.032 ,g, H]

[1, mole, O ,= 1, cancel{mole, O},times left(frac{15.999, g, O}{1,cancel{mole,O}} right), = 15.999 , g,O]

Adding the masses of our individual elements have:[12.011, g ,+ ,4.032,g, +, 15.999, g, =,32.042, g, CH_{3}OH]

As we were calculating the molar mass of CH_{3}OH we have

[32.042, g, CH_{3}OH, = ,1, mole ,CH_{3}OH]

Which we can use as a conversion factor

[frac{32.042, g, CH_{3}OH}{1, mole, CH_{3}OH}, or, frac{1, mole, CH_{3}OH}{32.042, g, CH_{3}OH}]

**We also know that for every molecule of CH _{3}OH we have 4 atoms of H. **

Now we can go back to the starting value given in the question:

[4.6,cancel{g, CH_{3}OH},times,left(frac{1, cancel{mole, CH_{3}OH}}{32.042,cancel{g,CH_{3}OH}}right)timesleft(frac{6.022, x, 10^{23},cancel{,molecules, CH_{3}OH}}{1 ,cancel{mole, CH_{3}OH}}right)timesleft(frac{4, atoms, H}{1 cancel{molecule ,CH_{3}OH}}right) = 3.5,x,10^{23}, atoms, H]

Exercise (PageIndex{6})

How many atoms of H are there in 2.06 grams of (ce{H_{2}O})?

*Answer*

1.38 x 10^{23} atoms H

Example (PageIndex{7}): Converting from Grams to grams

How many grams of oxygen are in 3.45 g of H_{3}PO_{4}

**Solution**

First we need to determine the mass of one mole of phosphoric acid (ce{H_{3}PO_{4}})

We have:

[3, mole, H ,= 3, cancel{mole, H},times left(frac{1.008, g, H}{1,cancel{mole,H}} right), = 3.024,g, H]

[1, mole, P ,= 1, cancel{mole, P},times left(frac{30.974, g, P}{1,cancel{mole,P}} right), = 30.974 ,g, P]

[4, mole, O ,= 4, cancel{mole, O},times left(frac{15.999, g, O}{1,cancel{mole,O}} right), = 63.996 ,g, O]

Adding the masses of our individual elements have:[3.024, g ,+ ,30.974,g, +, 63.996, g, =,97.994, g, H_{3}PO_{4}]

As we were calculating the molar mass of CH_{3}OH we have

[97.994, g, H_{3}PO_{4}, = ,1, mole ,H_{3}PO_{4}]

Which we can use as a conversion factor

[frac{97.994, g, H_{3}PO_{4}}{1, mole, H_{3}PO_{4}}, or, frac{1, mole, H_{3}PO_{4}}{97.994, g, H_{3}PO_{4}}]

To calculate the molar mass of (ce{H_{3}PO_{4}}) we used the idea that we have 3 moles of H, 1 mole of P and 4 moles of O for every one mole of (ce{H_{3}PO_{4}}). We recall that we can make our own conversion factors as long as the top and bottom are equal to each other. So much the same way I can give you four quarter or 1 dollar, if I hand you a mole of (ce{H_{3}PO_{4}}) I've handed you 3 mole of H, 1 mole of P and 4 moles of O. As this is true there is an additional set of conversion factors we can use:

[left(frac{3, moles, H}{1, mole, H_{3}PO_{4}}right), and , left(frac{1, mole, P}{1, mole, H_{3}PO_{4}}right), and, left(frac{4,moles, O}{1, mole, H_{3}PO_{4}}right)]

Now we can go back to the starting value given in the question:

[3.45,cancel{g,H_{3}PO_{4}},times,left(frac{1,cancel{mole,H_{3}PO_{4}}}{97.994,cancel{g,H_{3}PO_{4}}}right)timesleft(frac{4,cancel{mole,O}}{1,cancel{,mole, H_{3}PO_{4}}}right)timesleft(frac{15.999, g, O}{1 cancel{mole ,O}}right) = 2.25, g, O]

### Molar Mass Calculator

Exercise (PageIndex{6})

How many grams of H are there in 3.45 grams of (ce{H_{3}PO_{4}})?

*Answer*

0.106 grams H

## Summary

- The molecular mass (in amu) is the mass of one molecule of a compound
- The molar mass (in grams) is the mass of one mole of a compound or element.
- The molar mass is a useful conversion factor, which can be used to convert from grams to moles or from moles to grams.

## Contributors

CK-12 Foundation by Sharon Bewick, Richard Parsons, Therese Forsythe, Shonna Robinson, and Jean Dupon.

## ››Convert moles Gold to gram

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## ››More information from the unit converter

How many moles Gold in 1 grams?The answer is 0.0050770041918285.

We assume you are converting between **moles Gold** and **gram**.

You can view more details on each measurement unit:

molecular weight of Gold orgrams

The molecular formula for Gold is Au.

The SI base unit for **amount of substance** is the mole.

1 mole is equal to 1 moles Gold, or 196.96655 grams.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between moles Gold and gram.

Type in your own numbers in the form to convert the units!

## ››Quick conversion chart of moles Gold to grams

1 moles Gold to grams = 196.96655 grams

2 moles Gold to grams = 393.9331 grams

3 moles Gold to grams = 590.89965 grams

4 moles Gold to grams = 787.8662 grams

5 moles Gold to grams = 984.83275 grams

### List Of Molar Masses

6 moles Gold to grams = 1181.7993 grams

7 moles Gold to grams = 1378.76585 grams

8 moles Gold to grams = 1575.7324 grams

9 moles Gold to grams = 1772.69895 grams

10 moles Gold to grams = 1969.6655 grams

## ››Want other units?

You can do the reverse unit conversion fromgrams Gold to moles, or enter other units to convert below:

## ››Common amount of substance conversions

moles Gold to millimol

moles Gold to centimol

moles Gold to mole

moles Gold to kilomol

moles Gold to decimol

moles Gold to atom

moles Gold to picomol

moles Gold to molecule

moles Gold to nanomol

moles Gold to micromol

## ››Details on molecular weight calculations

In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

The atomic weights used on this site come from NIST, the National Institute of Standards and Technology. We use the most common isotopes. This is how to calculate molar mass (average molecular weight), which is based on isotropically weighted averages. This is not the same as molecular mass, which is the mass of a single molecule of well-defined isotopes. For bulk stoichiometric calculations, we are usually determining molar mass, which may also be called standard atomic weight or average atomic mass.

Using the chemical formula of the compound and the periodic table of elements, we can add up the atomic weights and calculate molecular weight of the substance.

Formula weights are especially useful in determining the relative weights of reagents and products in a chemical reaction. These relative weights computed from the chemical equation are sometimes called equation weights.

Finding molar mass starts with units of grams per mole (g/mol). When calculating molecular weight of a chemical compound, it tells us how many grams are in one mole of that substance. The formula weight is simply the weight in atomic mass units of all the atoms in a given formula.

### Molar Mass Of Gold(iii) Chloride

A common request on this site is to convert grams to moles. To complete this calculation, you have to know what substance you are trying to convert. The reason is that the molar mass of the substance affects the conversion. This site explains how to find molar mass.

If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. The percentage by weight of any atom or group of atoms in a compound can be computed by dividing the total weight of the atom (or group of atoms) in the formula by the formula weight and multiplying by 100.

## ››Metric conversions and more

### Convert Molar Mass To Grams

**ConvertUnits.com** provides an onlineconversion calculator for all types of measurement units.You can find metric conversion tables for SI units, as wellas English units, currency, and other data. Type in unitsymbols, abbreviations, or full names for units of length,area, mass, pressure, and other types. Examples include mm,inch, 100 kg, US fluid ounce, 6'3', 10 stone 4, cubic cm,metres squared, grams, moles, feet per second, and many more!